2(4x^2+7x)=3x^2=9x=35

Solution for 2(4x^2+7x)=3x^2=9x=35 equation:

2(4x^2+7x)=3x^2=9x=35

We move all terms to the left:

2(4x^2+7x)-(3x^2)=0

determiningTheFunctionDomain
-3x^2+2(4x^2+7x)=0

We multiply parentheses

-3x^2+8x^2+14x=0

We add all the numbers together, and all the variables

5x^2+14x=0

a = 5; b = 14; c = 0;
Δ = b2-4ac
Δ = 142-4·5·0
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{196}=14$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-14}{2*5}=\frac{-28}{10}
=-2+4/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+14}{2*5}=\frac{0}{10}
=0
$